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Oral Assessments Graduate 2020-01-09 3 74 S01 what we want to do is to sort the numbers in order (.) to
Oral Assessments Graduate 2020-01-09 3 75 S01 add into ∆one two three four five six seven eight∆↘
Oral Assessments Graduate 2020-01-09 3 76 UNK (0.7)
Oral Assessments Graduate 2020-01-09 3 77 S01 so what we did ☉last time☉ (0.4) is (0.9) uh we do it like this→
Oral Assessments Graduate 2020-01-09 3 78 S01 we've (.) uh go over the list of the remaining numbers
Oral Assessments Graduate 2020-01-09 3 79 S01 which is uh eight numbers right now→ so we (.) record
Oral Assessments Graduate 2020-01-09 3 80 S01 the (0.5) minimum number→ (0.5) uh in the list→
Oral Assessments Graduate 2020-01-09 3 81 S01 so (0.4) as we go on→ we'll- we'll find one is the uh
Oral Assessments Graduate 2020-01-09 3 82 S01 smallest number in the list→ and we put one in the
Oral Assessments Graduate 2020-01-09 3 83 S01 beginning of the (.) list we want uh (0.6) uh in the
Oral Assessments Graduate 2020-01-09 3 84 S01 result list↘
Oral Assessments Graduate 2020-01-09 3 85 S01 so (0.6) and then (0.9) after the ↑first (.) iteration uh
Oral Assessments Graduate 2020-01-09 3 86 S01 we (0.6) we go: (.) on into the remaining list which has
Oral Assessments Graduate 2020-01-09 3 87 S01 ↑seven numbers↘
Oral Assessments Graduate 2020-01-09 3 88 UNK (0.7)
Oral Assessments Graduate 2020-01-09 3 89 S01 so: right now↘ (1.0) we- (0.3) go on to the list and
Oral Assessments Graduate 2020-01-09 3 90 S01 find two as the smallest number↘
Oral Assessments Graduate 2020-01-09 3 91 UNK (0.6)
Oral Assessments Graduate 2020-01-09 3 92 S01 and then (0.8) we go on and on
Oral Assessments Graduate 2020-01-09 3 93 UNK (0.5)