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Course Level Date Clip# Line Interlocutor Content
Oral Assessments Graduate 2019-08-22 4 115 S01 so:→ we see→ that the electrical current→ (0.9) and the: standard
Oral Assessments Graduate 2019-08-22 4 116 S01 unit is ampere
Oral Assessments Graduate 2019-08-22 4 117 UNK (3.5)
Oral Assessments Graduate 2019-08-22 4 118 S01 and here we have current→ (.) voltage→ (.) xxx v
Oral Assessments Graduate 2019-08-22 4 119 S01 so this current (0.9) is observed (.) to be directly proportional
Oral Assessments Graduate 2019-08-22 4 120 S01 to the voltage (0.5) of the conductor↘
Oral Assessments Graduate 2019-08-22 4 121 UNK (0.8)
Oral Assessments Graduate 2019-08-22 4 122 S01 so voltage difference across the conductor↘
Oral Assessments Graduate 2019-08-22 4 123 UNK (0.7)
Oral Assessments Graduate 2019-08-22 4 124 S01 so this current (0.6) is directly proportional to the voltage→
Oral Assessments Graduate 2019-08-22 4 125 S01 so if the voltage increases→ the current also to the
Oral Assessments Graduate 2019-08-22 4 126 S01 conductor increases→
Oral Assessments Graduate 2019-08-22 4 127 UNK (0.4)
Oral Assessments Graduate 2019-08-22 4 128 S01 ∆the voltage decreases∆↘ ∆the current decreases∆↘
Oral Assessments Graduate 2019-08-22 4 129 UNK (0.5)
Oral Assessments Graduate 2019-08-22 4 130 S01 so to remove the proportionality→ let's introduce a constant
Oral Assessments Graduate 2019-08-22 4 131 S01 of proportionality→ (.) called g
Oral Assessments Graduate 2019-08-22 4 132 UNK (1.1)
Oral Assessments Graduate 2019-08-22 4 133 S01 this is the conductance of the conductor↘
Oral Assessments Graduate 2019-08-22 4 134 UNK (0.7)