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Course Level Date Clip# Line Interlocutor Content
Oral Assessments Graduate 2019-08-22 4 155 S01 and when we increase the voltage
Oral Assessments Graduate 2019-08-22 4 156 S01 so there's a voltage supply and we increase the voltage→
Oral Assessments Graduate 2019-08-22 4 157 S01 we see: that the current flowing through the conductor
Oral Assessments Graduate 2019-08-22 4 158 S01 also increases↘
Oral Assessments Graduate 2019-08-22 4 159 S01 ∆so that∆ a lot of the- there's there's more charge flowing
Oral Assessments Graduate 2019-08-22 4 160 S01 through↗ ⌈ (.) the time↘
Oral Assessments Graduate 2019-08-22 4 161 T01 ⌊ mm
Oral Assessments Graduate 2019-08-22 4 162 T01 okay↘
Oral Assessments Graduate 2019-08-22 4 163 S01 so it's the rate at which the flow (0.4) of charge right↗
Oral Assessments Graduate 2019-08-22 4 164 S01 so: (0.3) the: (.) the same time there's- there is more charge
Oral Assessments Graduate 2019-08-22 4 165 S01 that is flowing through
Oral Assessments Graduate 2019-08-22 4 166 UNK (0.4)
Oral Assessments Graduate 2019-08-22 4 167 T01 okay→
Oral Assessments Graduate 2019-08-22 4 168 UNK (0.3)
Oral Assessments Graduate 2019-08-22 4 169 S01 so yeah↘ so: we get to v equals i r→
Oral Assessments Graduate 2019-08-22 4 170 S01 and this resistance (0.5) is (.) directly proportional to
Oral Assessments Graduate 2019-08-22 4 171 S01 the length of the conductor→
Oral Assessments Graduate 2019-08-22 4 172 UNK (3.4)
Oral Assessments Graduate 2019-08-22 4 173 S01 and inversely proportional to the area of the conductor so→
Oral Assessments Graduate 2019-08-22 4 174 S01 the length increases→ the length of the conductor increases